Find the surface area of a rectangular pyramid with these measurements: l = 13 cm, w = 11 cm, and h = 8 cm. Express your answer as a decimal rounded to the nearest hundredth.(1 point)

Answer 1

The surface area of a rectangular pyramid can be found by adding the areas of all its faces.

The base of the pyramid is a rectangle with length l = 13 cm and width w = 11 cm. The area of the base is lw = 13 cm * 11 cm = 143 cm^2.

The remaining faces are triangles. There are 4 triangular faces in a rectangular pyramid.

The height of each triangular face is equal to the height of the pyramid, h = 8 cm.
The base of each triangular face is equal to one side of the base, either the length or the width of the rectangle.

The area of each triangular face can be found using the formula A = (1/2) * base * height.
For two faces with base l and height h, the area is (1/2) * l * h = (1/2) * 13 cm * 8 cm = 52 cm^2.
For the other two faces with base w and height h, the area is (1/2) * w * h = (1/2) * 11 cm * 8 cm = 44 cm^2.

Adding up the areas of all the faces, the surface area of the rectangular pyramid is 143 cm^2 + 52 cm^2 + 52 cm^2 + 44 cm^2 + 44 cm^2 = 335 cm^2.

Rounded to the nearest hundredth, the surface area of the rectangular pyramid is 335.00 cm^2. Answer: \boxed{335}.

Answer 2

wrong