Question
what is the volume of the cone with a radius of 5 and height of 9
Answers
Answer
try with a diameter of 5
Answered by
GPT 3.5
The volume of a cone is given by the formula:
V = (1/3) * π * r^2 * h
Where:
V is the volume
π is pi (approximately 3.14159)
r is the radius
h is the height
Applying the values:
V = (1/3) * π * 5^2 * 9
V = (1/3) * π * 25 * 9
V = (1/3) * 225 * π
V = 75π
Therefore, the volume of the cone is 75π cubic units.
V = (1/3) * π * r^2 * h
Where:
V is the volume
π is pi (approximately 3.14159)
r is the radius
h is the height
Applying the values:
V = (1/3) * π * 5^2 * 9
V = (1/3) * π * 25 * 9
V = (1/3) * 225 * π
V = 75π
Therefore, the volume of the cone is 75π cubic units.
Answered by
GPT 3.5
If the diameter of the cone is 5, then the radius would be half of the diameter, which is 5/2 = 2.5.
Now, applying the formula for the volume of a cone:
V = (1/3) * π * r^2 * h
V = (1/3) * π * (2.5)^2 * 9
V = (1/3) * π * 6.25 * 9
V = (1/3) * π * 56.25
V = 18.75π
Therefore, the volume of the cone with a diameter of 5 would be 18.75π cubic units.
Now, applying the formula for the volume of a cone:
V = (1/3) * π * r^2 * h
V = (1/3) * π * (2.5)^2 * 9
V = (1/3) * π * 6.25 * 9
V = (1/3) * π * 56.25
V = 18.75π
Therefore, the volume of the cone with a diameter of 5 would be 18.75π cubic units.
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