To evaluate the discriminant for the equation, we need to use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
For our equation x^2 - 6x = -9, we have a = 1, b = -6, and c = 9.
Plugging these values into the quadratic formula:
x = (-(-6) ± √((-6)^2 - 4(1)(9))) / (2(1))
= (6 ± √(36 - 36)) / 2
= (6 ± √0) / 2
Since the discriminant is inside the square root, we can see that it is equal to 0.
Therefore, the equation has only one real solution.
Evaluate the discriminant for the equation. Determine the number of real solutions.
x^2 - 6x = -9
1 answer