To solve this system of equations, we can use the method of substitution.
From the first equation, we can solve for y in terms of x:
3y - 2x = 21
3y = 2x + 21
y = (2x + 21)/3
Now we can substitute this expression for y in the second equation:
4((2x + 21)/3) + 5x = 5
Let's simplify and solve for x:
(8x + 84)/3 + 5x = 5
(8x + 84)/3 = 5 - 5x
8x + 84 = 15 - 15x
23x = -69
x = -3
Now we can substitute x = -3 into the first equation to find the value of y:
3y - 2(-3) = 21
3y + 6 = 21
3y = 15
y = 5
Therefore, the solution to the system of equations is x = -3 and y = 5.
3y- 2x=21
4y+ 5x=5
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