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Solve for

\[x\].

\[\dfrac{9^{x}}{9^3}=9^5\]
\[x=\]

1 answer

Using the properties of exponents, we have \[\frac{9^x}{9^3} = 9^5.\] Writing both sides with a common base, we have \[9^{x-3} = 9^5.\] Taking the logarithm of both sides with base 9, we have \[x-3 = 5.\] Adding 3 to both sides gives \[x = \boxed{8}.\]
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