The pH of a solution at 25°C in which [OH-]= 3.4 x 10-5 M is

Answer 1

To find the pH of a solution, we can use the equation:

pOH = -log[OH-]

Here, we are given [OH-] = 3.4 x 10^-5 M. Plugging this value into the equation, we find:

pOH = -log(3.4 x 10^-5)
= -(-4.47)
= 4.47

The next step is to find the pH using the relationship:

pH + pOH = 14

Plugging in the value of pOH, we find:

pH + 4.47 = 14

Subtracting 4.47 from both sides, we get:

pH = 14 - 4.47
= 9.53

Therefore, the pH of the solution is 9.53.