Use the properties of operations to add 9(k+13)+10(1/2k−1) .

Answer 1

To add 9(k+13) + 10(1/2k-1), we can distribute the numbers outside the parentheses and then combine like terms.

First, we distribute the 9 and 10:
= 9k + 9(13) + 10(1/2k) - 10(1)
Simplifying further, we have:
= 9k + 117 + 5k - 10

Now we combine like terms by adding the coefficients of k and the constants:
= (9k + 5k) + (117 - 10)
= 14k + 107