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Suppose 10 atoms of carbon react with 20 atoms of oxygen to form 10 molecules of carbon dioxide according to the law of convers...Asked by scienze
Suppose 10 atoms of carbon (C) react with 20 atoms of oxygen (O) to form 10 molecules of of carbon dioxide (CO2). According to the law of conservation, how many atoms are present in this reaction?
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Answered by
GPT 3.5
According to the law of conservation of mass, the number of atoms should remain constant before and after a chemical reaction.
In the given reaction, we have 10 atoms of carbon (C) and 20 atoms of oxygen (O).
To form carbon dioxide (CO2), each carbon (C) atom combines with 2 oxygen (O) atoms.
So, 10 atoms of carbon (C) will combine with 2 * 10 = 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (CO2).
In each molecule of carbon dioxide (CO2), there is 1 carbon (C) atom and 2 oxygen (O) atoms.
Therefore, in this reaction, we have a total of 10 carbon (C) atoms and 10 * 2 = 20 oxygen (O) atoms present.
In the given reaction, we have 10 atoms of carbon (C) and 20 atoms of oxygen (O).
To form carbon dioxide (CO2), each carbon (C) atom combines with 2 oxygen (O) atoms.
So, 10 atoms of carbon (C) will combine with 2 * 10 = 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (CO2).
In each molecule of carbon dioxide (CO2), there is 1 carbon (C) atom and 2 oxygen (O) atoms.
Therefore, in this reaction, we have a total of 10 carbon (C) atoms and 10 * 2 = 20 oxygen (O) atoms present.
Answered by
GPT 3.5
No, the correct answer is 40.
10 carbon (C) atoms + 20 oxygen (O) atoms = 10 carbon dioxide (CO2) molecules.
Each carbon dioxide (CO2) molecule contains 1 carbon (C) atom and 2 oxygen (O) atoms.
Therefore, in total, there are 10 carbon (C) atoms + (10 carbon dioxide (CO2) molecules * 1 carbon (C) atom) = 20 carbon (C) atoms, and
20 oxygen (O) atoms + (10 carbon dioxide (CO2) molecules * 2 oxygen (O) atoms) = 40 oxygen (O) atoms.
Hence, in this reaction, 40 atoms are present.
10 carbon (C) atoms + 20 oxygen (O) atoms = 10 carbon dioxide (CO2) molecules.
Each carbon dioxide (CO2) molecule contains 1 carbon (C) atom and 2 oxygen (O) atoms.
Therefore, in total, there are 10 carbon (C) atoms + (10 carbon dioxide (CO2) molecules * 1 carbon (C) atom) = 20 carbon (C) atoms, and
20 oxygen (O) atoms + (10 carbon dioxide (CO2) molecules * 2 oxygen (O) atoms) = 40 oxygen (O) atoms.
Hence, in this reaction, 40 atoms are present.
Answered by
GPT 3.5
Apologies for the mistake in my previous response. You are correct, and the correct answer is 30 atoms.
In the given reaction, we have 10 atoms of carbon (C) and 20 atoms of oxygen (O).
To form carbon dioxide (CO2), each carbon (C) atom combines with 2 oxygen (O) atoms.
Therefore, the 10 atoms of carbon (C) will combine with a total of 10 * 2 = 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (CO2).
So, in total, we have 10 atoms of carbon (C) and 20 atoms of oxygen (O).
Therefore, the total number of atoms present in this reaction is 10 + 20 = 30 atoms.
The correct answer is 30.
In the given reaction, we have 10 atoms of carbon (C) and 20 atoms of oxygen (O).
To form carbon dioxide (CO2), each carbon (C) atom combines with 2 oxygen (O) atoms.
Therefore, the 10 atoms of carbon (C) will combine with a total of 10 * 2 = 20 atoms of oxygen (O) to form 10 molecules of carbon dioxide (CO2).
So, in total, we have 10 atoms of carbon (C) and 20 atoms of oxygen (O).
Therefore, the total number of atoms present in this reaction is 10 + 20 = 30 atoms.
The correct answer is 30.
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