Asked by check answer
find the slope, if it exists, of the line containing the pair of points
(9,5) and (10,-3)
teh slope m= 1.2
m=(-3+9)/ (10-5)
m=6/5
m=1.2
(9,5) and (10,-3)
teh slope m= 1.2
m=(-3+9)/ (10-5)
m=6/5
m=1.2
Answers
Answered by
MathMate
Sorry, your answer is not correct. It is a big negative number.
The slope of a line passing between two points P1(x1,y1) and P2(x2,y2) is
m=(y2-y1)/(x2-x1) provided (x2-x1)≠0
I leave it to you to recalculate the slope required. Post your answer for verification if required.
The slope of a line passing between two points P1(x1,y1) and P2(x2,y2) is
m=(y2-y1)/(x2-x1) provided (x2-x1)≠0
I leave it to you to recalculate the slope required. Post your answer for verification if required.
Answered by
micheal
M= (y2-y1)/(x2-x1)
so (-3-5)/(10-9)=-7
so (-3-5)/(10-9)=-7
Answered by
MathMate
For -3-5 I get -8.
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