Asked by Jessica
Find the prime factorization for the integer
121
this is what I think as far as I go
11x11
am I right?
121
this is what I think as far as I go
11x11
am I right?
Answers
Answered by
MathMate
Right, but we usually write it as 11².
Answered by
Jessica
Simplify the expression. Assume all variables represent
nonzero real numbers.
-10b^5c^9/2b^5c^3
nonzero real numbers.
-10b^5c^9/2b^5c^3
Answered by
MathMate
Since it is a fraction, we look for like factors in the numerator and denominator and simplify accordingly.
Start with the coefficients:
(-10)/2 = -5
b<sup>5</sup>/b<sup>5</sup> = 1
c<sup>9</sup>/c<sup>3</sup> = c<sup>9-3</sup> = c<sup>6</sup>
So putting it altogether:
-10b^5c^9/2b^5c^3
= -5c<sup>6</sup>
Start with the coefficients:
(-10)/2 = -5
b<sup>5</sup>/b<sup>5</sup> = 1
c<sup>9</sup>/c<sup>3</sup> = c<sup>9-3</sup> = c<sup>6</sup>
So putting it altogether:
-10b^5c^9/2b^5c^3
= -5c<sup>6</sup>
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