Which of the following is an equivalent expression to 59⋅5−13 with only positive exponents that has been generated by applying the Properties of Integer Exponents?(1 point)
Responses
595−13
Start Fraction 5 superscript 9 baseline over 5 superscript negative 13 baseline End Fraction
154
Start Fraction 1 over 5 superscript 4 baseline end fraction
1625
Start Fraction 1 over 625 end fraction
54
9 answers
595(-13) is the correct equivalent expression with only positive exponents that has been generated by applying the Properties of Integer Exponents.
Which property of exponents was used to generate the equivalent expression 314 from 353−9 ?(1 point)
Responses
only the Property of Negative Exponents
only the Property of Negative Exponents
the Property of Negative Exponents and the Product Rule of Exponents
the Property of Negative Exponents and the Product Rule of Exponents
only the Power Rule of Exponents
only the Power Rule of Exponents
only the Product Rule of Exponents
Responses
only the Property of Negative Exponents
only the Property of Negative Exponents
the Property of Negative Exponents and the Product Rule of Exponents
the Property of Negative Exponents and the Product Rule of Exponents
only the Power Rule of Exponents
only the Power Rule of Exponents
only the Product Rule of Exponents
The Property of Negative Exponents was used to generate the equivalent expression 314 from 353(-9).
Which of the following is an equivalent expression to 150 ⋅ 7−2 (−4)−3 with only positive exponents that has been generated by applying the Properties of Integer Exponents?(1 point)
Responses
172 ⋅ (−4)−3
Start Fraction 1 over 7 squared times left parenthesis negative 4 right parenthesis superscript negative 3 baseline End Fraction
72(−4)3
Start Fraction 7 squared over left parenthesis negative 4 right parenthesis cubed end fraction
(−4)372
start fraction left parenthesis negative 4 right parenthesis cubed over 7 squared end fraction
4372
Responses
172 ⋅ (−4)−3
Start Fraction 1 over 7 squared times left parenthesis negative 4 right parenthesis superscript negative 3 baseline End Fraction
72(−4)3
Start Fraction 7 squared over left parenthesis negative 4 right parenthesis cubed end fraction
(−4)372
start fraction left parenthesis negative 4 right parenthesis cubed over 7 squared end fraction
4372
Start Fraction 1 over 7 squared times left parenthesis negative 4 right parenthesis superscript negative 3 baseline is the equivalent expression with only positive exponents that has been generated by applying the Properties of Integer Exponents.
Which of the following is the equivalent expression to (15−3 ⋅ 47)04−3 that has been generated by applying the Properties of Integer Exponents?(1 point)
Responses
604−3
Start Fraction 60 over 4 negative cubed end fraction
1⋅4−3
1 times 4 negative cubed
64
64
164
Responses
604−3
Start Fraction 60 over 4 negative cubed end fraction
1⋅4−3
1 times 4 negative cubed
64
64
164
604-3 is the equivalent expression to (15-3 ⋅ 47)04-3 that has been generated by applying the Properties of Integer Exponents.
Which of the following is an equivalent expression to (2−3 ⋅93)−429 ⋅9−10 with only positive exponents, generated by applying the Properties of Integer Exponents?(1 point)
Responses
23 ⋅92
2 cubed times 9 squared
212⋅9−1229⋅9−10
Start fraction 2 superscript 12 baseline times 9 superscript negative 12 baseline over 2 superscript 9 baseline times 9 superscript negative 10 baseline end fraction
2−7⋅9−129⋅9−10
Start fraction 2 superscript negative 7 baseline times 9 superscript negative 1 baseline over 2 superscript 9 baseline times 9 superscript negative 10 baseline end fraction
2392
Responses
23 ⋅92
2 cubed times 9 squared
212⋅9−1229⋅9−10
Start fraction 2 superscript 12 baseline times 9 superscript negative 12 baseline over 2 superscript 9 baseline times 9 superscript negative 10 baseline end fraction
2−7⋅9−129⋅9−10
Start fraction 2 superscript negative 7 baseline times 9 superscript negative 1 baseline over 2 superscript 9 baseline times 9 superscript negative 10 baseline end fraction
2392
Start fraction 2 superscript 12 baseline times 9 superscript negative 12 baseline over 2 superscript 9 baseline times 9 superscript negative 10 baseline end fraction is the equivalent expression to (2-3 ⋅93)-429 ⋅9-10 with only positive exponents, generated by applying the Properties of Integer Exponents.