The point-slope form of a linear equation is given by:
y - y1 = m(x - x1)
Where (x1, y1) represents a point on the line and m represents the slope of the line.
Given that the point (19, -12) lies on the line, and the slope is -3, we can substitute these values into the point-slope form to obtain the equation:
y - (-12) = -3(x - 19)
Simplifying this equation gives:
y + 12 = -3x + 57
Rearranging the terms to isolate y gives:
y = -3x + 57 - 12
Which simplifies to:
y = -3x + 45
Therefore, the equation of the line that passes through the point (19, -12) with a slope of -3 is y = -3x + 45.
Use point slope form to write the equation of a line that passes through the point (19, -12) wih a slope of -3
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