Use point-slope form to write the equation of a line that passes through the point (-7,-4, with slope 10/7

Answer 1

The point-slope form of a linear equation is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.

In this case, the point (-7, -4) is on the line and the slope is 10/7.

Substituting the values into the point-slope form, we have:

y - (-4) = (10/7)(x - (-7))

Simplifying the equation gives:

y + 4 = (10/7)(x + 7)

This can also be written as:

y + 4 = (10/7)x + 10

Rearranging the equation to get it in standard form, we subtract (10/7) x from both sides:

(10/7)x - y = 6

Multiplying through by 7 to eliminate the fraction, the equation becomes:

10x - 7y = 42

So, the equation of the line in point-slope form is y + 4 = (10/7)(x + 7), and in standard form is 10x - 7y = 42.