Use point-slope form to write the equation of a line that passes through the point left bracket, minus, 4, comma, 11, right bracket(−4,11) with slope minus, 2−2.

Answer 1

The point-slope form of a linear equation is given by:

y - y1 = m(x - x1)

Where (x1, y1) is a point on the line and m is the slope.

Given that the point is (-4, 11) and the slope is -2, we can substitute these values into the equation:

y - 11 = -2(x - (-4))

Simplifying this equation further:

y - 11 = -2(x + 4)

Distributing the -2 to the terms inside the parentheses:

y - 11 = -2x - 8

Adjusting the equation to put it in slope-intercept form (y = mx + b):

y = -2x - 8 + 11

Simplifying the equation further:

y = -2x + 3

Therefore, the equation of the line that passes through the point (-4,11) with a slope of -2 is y = -2x + 3.