Asked by jona
write the equatopm pf a line that passes through(3,-1) and is parrallel to the line y=-2x+1
Answers
Answered by
Reiny
doing it the easiest way ...
we know that the new equation differs only in the constant at the end, since the two lines are parallel.
so let the new equation be y = -2x + b
sub in the point...
-1 = -2(3) + b
5 = b
so y = -2x + 5
we know that the new equation differs only in the constant at the end, since the two lines are parallel.
so let the new equation be y = -2x + b
sub in the point...
-1 = -2(3) + b
5 = b
so y = -2x + 5
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