Asked by Crystal
Find each value of e^x to four decimal places:
A. e^10 which = e^(10)
B. (1/e^3)^2
(1/(e^3))^2 =
A. e^10 which = e^(10)
B. (1/e^3)^2
(1/(e^3))^2 =
Answers
Answered by
MathMate
Unless your school does not allow the use of calculators, in which case a table of logarithms will be supplied, I will assume that the use of calculators is permitted.
Most modern scientific calculators have the functions required to calculate the values above to 8 or 10 figures of accuracy. I will present the answers to 2-3 figurs of accuracy for you as a check.
If you have difficulties, or if calculators are not permitted, please post again.
A. e^10 which = e^(10)
If you have a TI algebraic calculator, press 10 and the buttins (2nd) and LN which is equivalent to e<sup>x</sup>.
You should get
e<sup>10</sup> = 22026.xxxx
B. (1/e^3)^2
(1/e^3)<sup>2</sup>
= (e<sup>-3</sup>)<sup>2</sup>
= e<sup>-6</sup>
= 0.00xx
Most modern scientific calculators have the functions required to calculate the values above to 8 or 10 figures of accuracy. I will present the answers to 2-3 figurs of accuracy for you as a check.
If you have difficulties, or if calculators are not permitted, please post again.
A. e^10 which = e^(10)
If you have a TI algebraic calculator, press 10 and the buttins (2nd) and LN which is equivalent to e<sup>x</sup>.
You should get
e<sup>10</sup> = 22026.xxxx
B. (1/e^3)^2
(1/e^3)<sup>2</sup>
= (e<sup>-3</sup>)<sup>2</sup>
= e<sup>-6</sup>
= 0.00xx
Answered by
Crystal
I got the answer to the first one. I finally figured out how to use that function. Thanks! NOW what about that second one? How do I punch in the numbers for this one? Thanks!
Answered by
MathMate
You do the same thing, except replace 10 with -6, something like
6 +/- (2nd) LN
6 +/- (2nd) LN
Answered by
Crystal
Got it thanks!
Answered by
MathMate
Great!
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