Which equation is the equation of a line that passes through (–10, 3) and is perpendicular to y = 5x – 7?

Question

(1 point)
Responses

y = 5x + 53
y = 5 x + 53

y = –one-fifthx – 7
y = – Image with alt text: one-fifth x – 7

y = –one-fifthx + 1
y = – Image with alt text: one-fifth x + 1

y = one-fifthx + 5

Answer 1

The equation of a line that is perpendicular to y = 5x - 7 will have a slope that is the negative reciprocal of 5, which is -1/5.

Using point-slope form, the equation of the line can be written as:
y - 3 = -1/5(x - (-10))

Simplifying, we get:
y - 3 = -1/5(x + 10)
y - 3 = -1/5x - 2
y = -1/5x + 1

Therefore, the equation of the line that passes through (-10, 3) and is perpendicular to y = 5x - 7 is y = -1/5x + 1.