The point-slope form of a linear equation is given by y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope.
In this case, the point (1, -5) is given and the slope m = -2. Plugging these values into the point-slope form, we get:
y - (-5) = -2(x - 1)
Simplifying,
y + 5 = -2x + 2
Subtracting 5 from both sides,
y = -2x - 3
So, the equation of the line in point-slope form passing through (1, -5) with a slope of -2 is y = -2x - 3.
Write an equation of the line in point-slope form passing through (1, -5) with a slope of -2.
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