Asked by Anonymous
I have to solve for side B of a right triangle. Side A is the square root of (25-x^2) and the hypotenuse is 5.
when i do A^2 + B^2 = C^2 then at the end i end up with
b^2 = -x^2 but the square root of a negative number is not possible so what am i doing wrong?
when i do A^2 + B^2 = C^2 then at the end i end up with
b^2 = -x^2 but the square root of a negative number is not possible so what am i doing wrong?
Answers
Answered by
Marth
You are given:
a = sqrt(25-x^2)
c = 5
So, a^2 + b^2 = c^2
25-x^2 + b^2 = 25
b^2 = x^2
b = x
a = sqrt(25-x^2)
c = 5
So, a^2 + b^2 = c^2
25-x^2 + b^2 = 25
b^2 = x^2
b = x