Question

Graph the information

Andrew started at home. For the first 20 minutes, he traveled a constant speed and traveled 5 miles. Cor the next 10 minutes he rested. Then drove home which took 20 minutes.

Answer 1

Wrong

Answer 2

What's the 4th graph plot if im now at 30,5

Answer 3

Write an equation from slope-intercept form based on the table below

x side: 0 , -6 , -12 , -18
y side: 1, -1, -3 , -5

y=?x+?

Answer 4

Write an equation from slope-intercept form using the table below

x side: 4 , 8 , 12
y side: 13 , 21 , 29

y=?x+?

Answer 5

write an equation from slope-intercept form using the table.

x side: 0 , 6 , 12 , 18
y side: 7 , 6 , 5 , 4

Y=?x+?

Answer 6

To graph this information, we can use a horizontal timeline as the x-axis, representing time in minutes, and a vertical line as the y-axis, representing distance in miles.

First, we'll mark Andrew's starting point at home on the x-axis.

2-------------------------------> (Time in minutes)

0------------------------------->

Next, we'll plot Andrew's movement for the first 20 minutes. He traveled at a constant speed of 5 miles, so we'll mark a point at (20, 5) on the graph.

2-------------------------------> (Time in minutes)

|
|
| *
|
0------------------------------->

After this, Andrew rested for the next 10 minutes. We'll mark this on the graph.

2-------------------------------> (Time in minutes)

|
|
*
| *
0------------------------------->

Finally, Andrew drove back home, which took 20 minutes. Since he would have traveled the same 5 miles back, we'll mark this point at (50, 5) on the graph.

2-------------------------------> (Time in minutes)

*
|
|
*
| *
0------------------------------->

This is the graph representing Andrew's journey.

Answer 7

Apologies for the mistake. Here is the correct graph:

First, we'll mark Andrew's starting point at home on the x-axis.

0-------------------------------> (Time in minutes)

0------------------------------->

Next, we'll plot Andrew's movement for the first 20 minutes. He traveled at a constant speed of 5 miles, so we'll mark a point at (20, 5) on the graph.

0-------------------------------> (Time in minutes)

|
|
* |
|
0------------------------------->

After this, Andrew rested for the next 10 minutes. We'll mark this on the graph.

0-------------------------------> (Time in minutes)

|
* |
|
* |
0------------------------------->

Finally, Andrew drove back home, which took 20 minutes. Since he would have traveled the same 5 miles back, we'll mark this point at (30, 0) on the graph.

0-------------------------------> (Time in minutes)

* |
|
* |
0------------------------------->

This is the corrected graph representing Andrew's journey.

Answer 8

If Andrew is located at (30, 5), then the fourth point on the graph would correspond to this position. Here is the updated graph:

0-------------------------------> (Time in minutes)

* |
|
* |
0------------------------------->

*
|
* |
0------------------------------->

This represents Andrew's position at (30, 5) on the graph.

Answer 9

To find the equation in slope-intercept form (y = mx + b), we need to determine the values of the slope (m) and the y-intercept (b).

To find the slope (m), we can use the formula:
m = (change in y) / (change in x)

Using the values from the table:
(change in y) = -5 - 1 = -6
(change in x) = -18 - 0 = -18

m = (-6) / (-18) = 1/3

Now, to find the y-intercept (b), we can substitute the values of x and y from any point in the table into the slope-intercept form equation and solve for b.

Let's choose the point (0, 1):

1 = (1/3)(0) + b

1 = b

Therefore, b = 1.

Now we can write the equation in slope-intercept form:

y = (1/3)x + 1

Answer 10

To find the equation in slope-intercept form (y = mx + b), we need to determine the values of the slope (m) and the y-intercept (b).

To find the slope (m), we can use the formula:
m = (change in y) / (change in x)

Using the values from the table:
(change in y) = 29 - 13 = 16
(change in x) = 12 - 4 = 8

m = 16 / 8 = 2

Now, to find the y-intercept (b), we can substitute the values of x and y from any point in the table into the slope-intercept form equation and solve for b.

Let's choose the point (4, 13):

13 = 2(4) + b

13 = 8 + b

b = 13 - 8 = 5

Therefore, b = 5.

Now we can write the equation in slope-intercept form:

y = 2x + 5

Answer 11

To find the equation in slope-intercept form (y = mx + b), we need to determine the values of the slope (m) and the y-intercept (b).

To find the slope (m), we can use the formula:
m = (change in y) / (change in x)

Using the values from the table:
(change in y) = 4 - 7 = -3
(change in x) = 18 - 0 = 18

m = -3 / 18 = -1/6

Now, to find the y-intercept (b), we can substitute the values of x and y from any point in the table into the slope-intercept form equation and solve for b.

Let's choose the point (0, 7):

7 = (-1/6)(0) + b

7 = b

Therefore, b = 7.

Now we can write the equation in slope-intercept form:

y = (-1/6)x + 7