Asked by gnarls
how you would express [c0s(2x)/sinx ]+ [sin(2x)/cosx]
Answers
Answered by
MathMate
Use trigonometric identities to simplify to 1/sin(x).
The identities required are:
cos(2x) = cos<sup>2</sup>(x) - sin<sup>2</sup>(x)
sin(2x) = 2sin(x)cos(x)
cos<sup>2</sup>(x) + sin<sup>2</sup>(x) = 1
The identities required are:
cos(2x) = cos<sup>2</sup>(x) - sin<sup>2</sup>(x)
sin(2x) = 2sin(x)cos(x)
cos<sup>2</sup>(x) + sin<sup>2</sup>(x) = 1
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