FACTOR 12Y+ 6 USING THE GCF

Answer 1

To factor 12y + 6 using the GCF (Greatest Common Factor), we need to find the largest number or variable that can divide evenly into both terms.

First, we identify the factors of each term:
12y: 1, 2, 3, 4, 6, 12, y, 2y, 3y, 4y, 6y, 12y
6: 1, 2, 3, 6

Now, let's find the common factors:
The common factors of 12y and 6 are 1, 2, 3, and 6.

We take the largest common factor, which is 6, and divide both terms by it:
(12y + 6) / 6 = 2y + 1

Therefore, the factored form of 12y + 6 using the GCF is 6(2y + 1).

Answer 2

ADD : 5(0.5 - 1) + 2 ( 0.4 - K). ANSWER SHOULD BE IN DECIMAL FROM (1 POINT)

Answer 3

To find the sum of 5(0.5 - 1) + 2(0.4 - k), we need to distribute the numbers outside the parentheses and then combine like terms.

First, distribute 5 and 2:
5(0.5 - 1) + 2(0.4 - k)
= 2.5 - 5 + 0.8 - 2k

Next, combine like terms:
= (2.5 + 0.8) - (5 + 2k)
= 3.3 - 5 - 2k

Finally, simplify further to obtain the answer:
= -1.7 - 2k

Therefore, the sum 5(0.5 - 1) + 2(0.4 - k) in decimal form is -1.7 - 2k.

Answer 4

SUBTRACT 1/2 (z+4) -3 (1/4z + 1). USE FRACTIONS IN FINAL FORM (1 POINT)

Answer 5

To subtract 1/2(z + 4) - 3(1/4z + 1), we need to distribute the coefficients outside the parentheses and then combine like terms.

First, distribute 1/2 and -3:
1/2(z + 4) - 3(1/4z + 1)
= (1/2)z + (1/2)4 - 3(1/4)z - 3(1)

Simplify the expressions:
= (1/2)z + 2 - (3/4)z - 3

Next, combine like terms:
= (1/2)z - (3/4)z + 2 - 3

To combine the z terms, we need to find a common denominator, which is 4:
= (2/4)z - (3/4)z + 2 - 3
= -(1/4)z - 1

Therefore, the subtraction of 1/2(z + 4) - 3(1/4z + 1) in final fraction form is -(1/4)z - 1.

Answer 6

SUBTRACT: (3B-2C) - (6C+2B) - (B+C).

Answer 7

To subtract (3B-2C) - (6C+2B) - (B+C), we need to distribute the negative signs and combine like terms.

Distributing the negative sign in front of each parentheses:
=3B - 2C - 6C - 2B - B - C

Now, let's combine the like terms:
=(3B - 2B - B) + (-2C - 6C - C)
=0B - 3B - 9C
=-3B - 9C

Therefore, the subtraction of (3B-2C) - (6C+2B) - (B+C) is -3B - 9C.