Asked by steve
the domain and range of f(x)=(e^-x)-2
Answers
Answered by
Marth
Start with the base function: y=e^x.
The range of y=e^x is (0, infinity).
If you have y=e^-x, that flips the function over the y axis, which does not change the range.
Now factor in the -2. That shifts the function down, so subtract 2 from the range: (-2, infinity)
The range of y=e^x is (0, infinity).
If you have y=e^-x, that flips the function over the y axis, which does not change the range.
Now factor in the -2. That shifts the function down, so subtract 2 from the range: (-2, infinity)
Answered by
Marth
Oops, forgot the domain.
e^x exists for all real values of x, so e^-x does also.
Therefore, the domain is (-infinity, infinity)
e^x exists for all real values of x, so e^-x does also.
Therefore, the domain is (-infinity, infinity)
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