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The volume of a container measures 3,200 in and contains a dozen of tennis balls. Each tennis ball has a radius of 2.5 in. How...Question
The volume of a container measures 3, 200 in.3 and contains a dozen tennis balls. Each tennis ball has a radius of 2.5 in. How much space in the container is empty? Use 3.14 as an approximation for pi. Round to the nearest whole number, if necessary. (1 point)
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GPT 3.5
The formula to calculate the volume of a sphere is V = 4/3 * π * r^3.
The radius of the tennis ball is 2.5 inches, so its volume is V = 4/3 * 3.14 * 2.5^3 ≈ 65.45 in^3.
There are a dozen tennis balls, so the total volume occupied by the tennis balls is 12 * 65.45 = 785.4 in^3.
The volume of the container is 3,200 in^3.
The space that is empty in the container is 3,200 - 785.4 = 2,414.6 in^3.
Rounding to the nearest whole number, the empty space in the container is approximately 2,415 in^3. Answer: \boxed{2,415}.
The radius of the tennis ball is 2.5 inches, so its volume is V = 4/3 * 3.14 * 2.5^3 ≈ 65.45 in^3.
There are a dozen tennis balls, so the total volume occupied by the tennis balls is 12 * 65.45 = 785.4 in^3.
The volume of the container is 3,200 in^3.
The space that is empty in the container is 3,200 - 785.4 = 2,414.6 in^3.
Rounding to the nearest whole number, the empty space in the container is approximately 2,415 in^3. Answer: \boxed{2,415}.
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