To find how much money Jacqueline will earn at her two jobs this week, we need to substitute the given values of l=5 and s=7 in the expression 15l+12s:
15(5) + 12(7) = 75 + 84 = 159
Therefore, Jacqueline will earn $159 at her two jobs this week.
Jacqueline has two part-time jobs. She earns $15 per hour, l , working as a lab assistant, and $12 per hour, s , working as a cashier. This is modeled by 15l+12s . Evaluate for l=5 and s=7 to find how much money Jacqueline will earn at her two jobs this week. simple answer pls
11 answers
Find the GCF of 20x − 4
To find the greatest common factor (GCF) of 20x − 4, we need to factor out the common factors of the terms 20x and -4.
The prime factorization of 20 is 2 * 2 * 5, and the GCF of 20x and -4 includes the 2 factor, so we can factor out a 2:
20x − 4 = (2 * 10x) − (2 * 2) = 2(10x − 2)
The GCF of 20x − 4 is 2.
The prime factorization of 20 is 2 * 2 * 5, and the GCF of 20x and -4 includes the 2 factor, so we can factor out a 2:
20x − 4 = (2 * 10x) − (2 * 2) = 2(10x − 2)
The GCF of 20x − 4 is 2.
Find the GCF of 30m + 12n .
To find the greatest common factor (GCF) of 30m + 12n, we need to factor out the common factors of the terms 30m and 12n.
The prime factorization of 30 is 2 * 3 * 5, and the prime factorization of 12 is 2 * 2 * 3. The GCF of 30m and 12n includes the common factors 2 and 3.
Next, we need to look at the variables m and n. In the expression 30m + 12n, there is no common power of m and n that can be factored out.
Therefore, the GCF of 30m + 12n is 2 * 3 = 6.
The prime factorization of 30 is 2 * 3 * 5, and the prime factorization of 12 is 2 * 2 * 3. The GCF of 30m and 12n includes the common factors 2 and 3.
Next, we need to look at the variables m and n. In the expression 30m + 12n, there is no common power of m and n that can be factored out.
Therefore, the GCF of 30m + 12n is 2 * 3 = 6.
Factor 8a − 28 using the GCF
To factor 8a − 28 using the greatest common factor (GCF), we need to find the largest factor that both terms, 8a and -28, have in common.
First, let's factor out the GCF of 8a and -28. The prime factorization of 8 is 2 * 2 * 2, and the prime factorization of 28 is 2 * 2 * 7.
The GCF of 8 and 28 is 2 * 2 = 4.
Next, we need to look at the variable a. In the expression 8a − 28, there is no common power of a that can be factored out.
Therefore, we can write 8a − 28 as:
8a − 28 = 4(2a − 7).
First, let's factor out the GCF of 8a and -28. The prime factorization of 8 is 2 * 2 * 2, and the prime factorization of 28 is 2 * 2 * 7.
The GCF of 8 and 28 is 2 * 2 = 4.
Next, we need to look at the variable a. In the expression 8a − 28, there is no common power of a that can be factored out.
Therefore, we can write 8a − 28 as:
8a − 28 = 4(2a − 7).
Add: 5(0.5k−1)+2(0.4−k) . Answer should be in decimal form
To add 5(0.5k - 1) + 2(0.4 - k), we distribute the coefficients:
5(0.5k - 1) + 2(0.4 - k) = 2.5k - 5 + 0.8 - 2k
Now, we can simplify by combining like terms:
2.5k - 5 + 0.8 - 2k = (2.5k - 2k) + (-5 + 0.8)
Simplifying further gives:
0.5k - 4.2
Therefore, the final answer is 0.5k - 4.2.
5(0.5k - 1) + 2(0.4 - k) = 2.5k - 5 + 0.8 - 2k
Now, we can simplify by combining like terms:
2.5k - 5 + 0.8 - 2k = (2.5k - 2k) + (-5 + 0.8)
Simplifying further gives:
0.5k - 4.2
Therefore, the final answer is 0.5k - 4.2.
Subtract 12(z+4)−3(14z+1) . Use fractions in final form.
To subtract 12(z + 4) - 3(14z + 1), we can distribute the coefficients:
12(z + 4) - 3(14z + 1) = 12z + 48 - (42z + 3)
Now we can simplify by removing the parentheses:
12z + 48 - (42z + 3) = 12z + 48 - 42z - 3
Next, we can combine like terms:
12z + 48 - 42z - 3 = (12z - 42z) + (48 - 3) = -30z + 45
Therefore, the final answer is -30z + 45.
12(z + 4) - 3(14z + 1) = 12z + 48 - (42z + 3)
Now we can simplify by removing the parentheses:
12z + 48 - (42z + 3) = 12z + 48 - 42z - 3
Next, we can combine like terms:
12z + 48 - 42z - 3 = (12z - 42z) + (48 - 3) = -30z + 45
Therefore, the final answer is -30z + 45.
15 answers