2KOH + H2SO4 ==> K2SO4 + 2H2O
mols H2SO4 = M x L = ?
mols KOH = 1/2 that (from the coefficients in the balanced equation)
Then M KOH = mols KOH/L KOH
23.8 ml of a 2.0 mol/l surfuric acid solution reacted completely with 68.0 ml of potassium hydroxide. find the concentration of potassium hydroxide
2 answers
there is one mole of H2SO4
AND TWO MOLES OF KOH
0.0476 MOLE H2SO4(2MOLES KOH/ONE MOLE H2SO4)
TWICE THAT OF THE BALANCED EQUATION
0.0952 MOL KOH/0.068 LITERS KOH =1.4 MOLE/LITER KOH
AND TWO MOLES OF KOH
0.0476 MOLE H2SO4(2MOLES KOH/ONE MOLE H2SO4)
TWICE THAT OF THE BALANCED EQUATION
0.0952 MOL KOH/0.068 LITERS KOH =1.4 MOLE/LITER KOH
4 answers