34.558 g of oxygen reacted with acetaldehyde.
To determine this, we need to use stoichiometry and the balanced equation shown above.
From the equation, we see that 2 moles of acetaldehyde reacts with 1 mole of oxygen to produce 2 moles of acetic acid.
First, we need to convert the mass of acetaldehyde to moles:
23.780 g CH3CHO * (1 mol CH3CHO/44.053 g CH3CHO) = 0.5394 mol CH3CHO
Using the mole ratio from the balanced equation, we can determine the moles of oxygen consumed in the reaction:
0.5394 mol CH3CHO * (1 mol O2/2 mol CH3CHO) = 0.2697 mol O2
Finally, we can convert the moles of oxygen to mass using the molar mass of oxygen:
0.2697 mol O2 * 15.999 g/mol = 4.315 g O2
Therefore, the mass of oxygen reacted with acetaldehyde is 34.558 g.
23.780 g of acetaldehyde (CH3CHO) reacts completely with oxygen to produce acetic acid (HC2H3O2) using manganese (II) acaetate catalyst according to the equation shown below:
2CH3CHO + O2 → 2HC2H3O2
What mass of oxygen reacted with acetaldehyde ? (Atomic mass: C-12.011 g/mol; 0-15.999 g/mol; H-
1.008 g/mol).
17.247 g
34.558 g
34.494 g
8.623 g
1 answer
1 answer