To find the value of b, we can use the fact that the sum of the solutions of a quadratic equation of the form ax^2 + bx + c = 0 is equal to -b/a.
In this case, the sum of the solutions is -11 + 5 = -6.
So, we need to find the value of b when -b/a = -6.
Plugging in the given values, we have:
-b/1 = -6
b = 6
Therefore, the value of b should be 6.
What should be the value of b in x2+bx−55=0 so that its solutions are −11 and 5? (1 point)
Responses
6
6
−16
negative 16
16
16
−6
1 answer