m2a=m2g-m1a

m2a+m1a=m2g
a= m2g/(m1+m2)

I got this

m2a=m2g-m1a

m2a + m1 a = m2g-m1a + m1 a

m2 a + m1 a = m2g

(m2 a + m1 a = m2g(m2 + m1)^-1 = a + a = (m2 + m1)^-1 m2g

a + a = (m2 + m1)^-1 m2g
2a = (m2 + m1)^-1 m2g

(2a = (m2 + m1)^-1 m2g)2^-1 = a = (2(m2 + m1))^-1 m2g

a = (2(m2 + m1))^-1 m2g

Please show me what I did wrong.
Thank You!

2 answers

At the step "m2 a + m1 a = m2g," you can factor out an a using the distributive property:

a(m2 + m1) = m2g

Now divide both sides by (m2 + m1):

a = m2g / (m2 + m1)
thank you so much