To find the first four terms of the sequence, we can use the given formula: aₙ = 3aₙ₋₁.
We're given that a₁ = 6. Using the formula, we can find the next terms:
a₂ = 3a₁ = 3 * 6 = 18
a₃ = 3a₂ = 3 * 18 = 54
a₄ = 3a₃ = 3 * 54 = 162
Therefore, the first four terms of the sequence are: 6, 18, 54, 162.
where A sequence can be generated by using a n =3a \ n-1\; a_{1} = 6 and is a whole number greater than 1. What are the first four terms of the sequence?
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