Subtract 12(z+4)−3(14z+1) . Use fractions in final form.(1 point)

To simplify the expression, we must distribute the coefficients to the terms inside the parentheses and combine like terms.

Starting with the first part of the expression, $12(z+4)$:
$$12(z+4)=12z+12(4)=12z+48$$

Now, let's simplify the second part, $3(14z+1)$:
$$3(14z+1)=3\cdot14z+3\cdot1=42z+3$$

Putting it all together, the expression becomes:
$$12(z+4)-3(14z+1)=(12z+48)-(42z+3)$$

Now, we can distribute the negative sign to the terms inside the second parentheses:
$$=12z+48-42z-3$$

Next, we can combine like terms by grouping the $z$ terms and the constant terms:
$$=(12z-42z)+(48-3)$$
$$=(-30z)+(45)$$

Thus, the final simplified form of the expression is $$-30z+45$$