To find the solution to both equations, we can use the method of substitution or elimination. Let's use the method of elimination.
We start by multiplying the first equation by 3 and the second equation by -5 to make the coefficients of x in both equations the same:
3(x-5y) = 3(7) => 3x - 15y = 21
-5(3x-2y) = -5(-4) => -15x + 10y = 20
Now, we can add the two equations together to eliminate the x term:
(3x - 15y) + (-15x + 10y) = 21 + 20
-12y = 41
Solving for y, we divide both sides of the equation by -12:
y = (-41) / (-12) = 41/12
Now that we have the value of y, we can substitute it back into one of the original equations to solve for x. Let's use the first equation:
x - 5(41/12) = 7
x - 205/12 = 7
x = 7 + 205/12
x = 84/12 + 205/12
x = 289/12
Therefore, the solution to both equations is (x, y) = (289/12, 41/12).
x-5y=7 and 3x-2y=-4 find the solution to both equations
the intersection point is
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