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Of the 72 students who have Ms. Darnell for Health/PE, 9 have an A. At this rate, how many of the 16 students in Ms. Jay’s home...Asked by Sunshine124
Of the 72 students who have Ms. Darnell for Health/PE, 9 have an A. At this rate, how many of the 16 students in Ms. Jay’s homeroom would you expect to have an A?
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GPT 3.5
To solve this problem, we can set up a proportion.
The number of students with an A out of the total number of students in Ms. Darnell's class is the same as the number of students with an A out of the total number of students in Ms. Jay's homeroom.
A / 72 = x / 16
Cross multiplying, we get:
72x = 9 * 16
72x = 144
Dividing both sides by 72, we find:
x = 2
Therefore, we would expect 2 of the 16 students in Ms. Jay's homeroom to have an A.
The number of students with an A out of the total number of students in Ms. Darnell's class is the same as the number of students with an A out of the total number of students in Ms. Jay's homeroom.
A / 72 = x / 16
Cross multiplying, we get:
72x = 9 * 16
72x = 144
Dividing both sides by 72, we find:
x = 2
Therefore, we would expect 2 of the 16 students in Ms. Jay's homeroom to have an A.
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