a) To solve for x and y in this system of linear equations:
2x + 3y = 4 ---(1)
x + 2y = 2 ----(2)
Rearranging equation (2) to solve for x gives:
x = 2 - 2y
Substituting this value of x into equation (1) gives:
2(2 - 2y) + 3y = 4
4 - 4y + 3y = 4
-y = 0
y = 0
Substituting the value of y back into equation (2):
x + 2(0) = 2
x = 2
Therefore, the solution to the system is x = 2 and y = 0.
b) To solve for x and y in this system of linear equations:
x + y = 2 ----(1)
2x + 2y = 4 ---(2)
Dividing equation (2) by 2 gives:
x + y = 2 ---(3)
We can see that equations (1) and (3) are the same equation, which means they represent the same line. Therefore, there are infinitely many solutions to this system of equations. Any values of x and y that satisfy the equation x + y = 2 will be a valid solution.
c) To solve for x and y in this system of linear equations:
x + y = 5 ----(1)
x + y = 9 ----(2)
Subtracting equation (1) from equation (2) gives:
(x + y) - (x + y) = 9 - 5
0 = 4
This equation is not possible since 0 cannot equal 4. Therefore, there is no solution to this system of equations.
5.Using system linear equation solve for x&y.
a, 2x+3y=4
x+2y=2
b, x+y=2
2x+2y=4
c, x+y=5
X+y=9
1 answer