Find the det of 1 -2 0

Question

-2 2 3
0 1 4

Answer 1

To find the determinant of a 3x3 matrix, we can use the formula:

det(A) = a(ei - fh) - b(di - fg) + c(dh - eg)

In this case, the matrix is:

1 -2 0
-2 2 3
0 1 4

Using the formula, we have:

det(A) = 1(2*4 - 3*1) - (-2)(-2*4 - 3*0) + 0(-2*1 - 2*0)

Simplifying this expression, we get:

det(A) = 1(8 - 3) - (-2)(-8) + 0(0)

det(A) = 5 - 16 + 0

det(A) = -11

Therefore, the determinant of the given matrix is -11.