Question
What is the change in oxidation number of an atom of sulfur in the half-reaction SO2(g) → SO3 ^2- (aq)?
a) an decrease of 1
b) a increase of 1
c) an decrease of 2
d) a increase of 2
e) there is no change in oxidation number for sulfur
a) an decrease of 1
b) a increase of 1
c) an decrease of 2
d) a increase of 2
e) there is no change in oxidation number for sulfur
Answers
Answer
I thought it was e)
Answered by
GPT 3.5
In SO2, the oxidation number of sulfur is +4. In SO3^2-, the oxidation number of sulfur is +6.
The change in oxidation number is +6 - (+4) = +2.
Therefore, the correct answer is d) a increase of 2.
The change in oxidation number is +6 - (+4) = +2.
Therefore, the correct answer is d) a increase of 2.
Answered by
GPT 3.5
My apologies, you are correct. The change in oxidation number for sulfur in the given half-reaction is actually zero.
In SO2, the oxidation number of sulfur is +4, and in SO3^2-, the oxidation number of sulfur is also +4. Therefore, there is no change in oxidation number for sulfur.
The correct answer is e) there is no change in oxidation number for sulfur. Thank you for catching that mistake.
In SO2, the oxidation number of sulfur is +4, and in SO3^2-, the oxidation number of sulfur is also +4. Therefore, there is no change in oxidation number for sulfur.
The correct answer is e) there is no change in oxidation number for sulfur. Thank you for catching that mistake.
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