Which of the following is an ordered pair of the relation y=−2/3x+6 ?

Answer 1

To determine if a pair of values is an ordered pair of the relation, we need to substitute the x-value into the equation and see if it gives us the corresponding y-value.

Let's check each option:

(a) (2, 5):
When x = 2, we have:
y = -2/3 * 2 + 6
y = -4/3 + 6
y = 6 - 4/3
y = 18/3 - 4/3
y = 14/3

So, (2, 14/3) is an ordered pair of the relation.

(b) (4, -4):
When x = 4, we have:
y = -2/3 * 4 + 6
y = -8/3 + 6
y = 18/3 - 8/3
y = 10/3

So, (4, 10/3) is an ordered pair of the relation.

(c) (0, 3):
When x = 0, we have:
y = -2/3 * 0 + 6
y = 0 + 6
y = 6

So, (0, 6) is an ordered pair of the relation.

(d) (-2, -2):
When x = -2, we have:
y = -2/3 * -2 + 6
y = 4/3 + 6
y = 18/3 + 4/3
y = 22/3

So, (-2, 22/3) is an ordered pair of the relation.

Therefore, the correct answer is:

(a) (2, 5)

Answer 2

only answers are
(3,4)

(0,−23)

(3,8)

(1,4)

Answer 3

To determine if each option is an ordered pair of the relation, we need to substitute the x-value into the equation and see if it gives us the corresponding y-value.

Let's check each option:

(a) (3, 4):
When x = 3, we have:
y = -2/3 * 3 + 6
y = -6/3 + 6
y = 0 + 6
y = 6

Since y = 4, (3, 4) is not an ordered pair of the relation.

(b) (0, -23):
When x = 0, we have:
y = -2/3 * 0 + 6
y = 0 + 6
y = 6

Since y = -23, (0, -23) is not an ordered pair of the relation.

(c) (3, 8):
When x = 3, we have:
y = -2/3 * 3 + 6
y = -6/3 + 6
y = 0 + 6
y = 6

Since y = 8, (3, 8) is not an ordered pair of the relation.

(d) (1, 4):
When x = 1, we have:
y = -2/3 * 1 + 6
y = -2/3 + 6
y = 18/3 - 2/3
y = 16/3

Since y = 4, (1, 4) is an ordered pair of the relation.

Therefore, the correct answer is:

(d) (1, 4)

Answer 4

everyone here is wrong, the answer is (3, 4)