To solve this system of equations, you can use the method of elimination. By adding the two equations together, you can eliminate the variable "y" and solve for "x".
Adding the two equations together, (6x-5y) + (3x+5y) = 27 + 36.
This simplifies to 9x = 63.
Dividing both sides of the equation by 9, you get x = 7.
Now plug this value of x back into one of the original equations to solve for y. Let's use the first equation:
6x - 5y = 27.
Substitute x = 7:
6(7) - 5y = 27.
Simplify:
42 - 5y = 27.
Subtract 42 from both sides:
-5y = -15.
Divide both sides by -5:
y = 3.
Therefore, the solution to the system of equations is (7, 3).
Solve the system of equations.
6x-5y=27
3x+5y=36
(__,__)
10 answers
solve the system of equations.
2x+8y=8
2x-4y=-16
(___,___)
2x+8y=8
2x-4y=-16
(___,___)
To solve this system of equations, we can use the method of elimination. By subtracting the second equation from the first equation, we can eliminate the variable "x" and solve for "y".
(2x + 8y) - (2x - 4y) = 8 - (-16)
This simplifies to 12y = 24
Dividing both sides of the equation by 12, we get y = 2.
Now we can substitute the value of y back into either of the original equations to solve for x. Let's use the first equation:
2x + 8(2) = 8
Simplifying, we get 2x + 16 = 8
Subtracting 16 from both sides, we get 2x = -8
Dividing both sides by 2, we get x = -4.
Therefore, the solution to the system of equations is (-4, 2).
(2x + 8y) - (2x - 4y) = 8 - (-16)
This simplifies to 12y = 24
Dividing both sides of the equation by 12, we get y = 2.
Now we can substitute the value of y back into either of the original equations to solve for x. Let's use the first equation:
2x + 8(2) = 8
Simplifying, we get 2x + 16 = 8
Subtracting 16 from both sides, we get 2x = -8
Dividing both sides by 2, we get x = -4.
Therefore, the solution to the system of equations is (-4, 2).
Solve the system of equations.
7x+3y=-25
-7x+9y=-47
(___,___)
7x+3y=-25
-7x+9y=-47
(___,___)
To solve this system of equations, we can use the method of elimination. By adding the two equations together, we can eliminate the variable "x" and solve for "y".
(7x + 3y) + (-7x + 9y) = -25 + (-47)
Simplifying, we get 12y = -72
Dividing both sides of the equation by 12, we get y = -6
Now we can substitute the value of y back into either of the original equations to solve for x. Let's use the first equation:
7x + 3(-6) = -25
Simplifying, we get 7x - 18 = -25
Adding 18 to both sides, we get 7x = -7
Dividing both sides by 7, we get x = -1
Therefore, the solution to the system of equations is (-1, -6).
(7x + 3y) + (-7x + 9y) = -25 + (-47)
Simplifying, we get 12y = -72
Dividing both sides of the equation by 12, we get y = -6
Now we can substitute the value of y back into either of the original equations to solve for x. Let's use the first equation:
7x + 3(-6) = -25
Simplifying, we get 7x - 18 = -25
Adding 18 to both sides, we get 7x = -7
Dividing both sides by 7, we get x = -1
Therefore, the solution to the system of equations is (-1, -6).
Solve the system of equations.
-x+6y=13
4x-10y=-10
(___,___)
-x+6y=13
4x-10y=-10
(___,___)
To solve this system of equations, we can use the method of elimination.
First, let's multiply the first equation by 4 to make the coefficient of "-x" the same as the coefficient of "4x" in the second equation:
4(-x + 6y) = 4(13)
-4x + 24y = 52
Now we can add this new equation to the second equation to eliminate the variable "x":
(-4x + 24y) + (4x - 10y) = 52 + (-10)
14y = 42
Dividing both sides of the equation by 14, we get:
y = 3
Now we can plug this value of y back into either of the original equations to solve for x. Let's use the first equation:
-x + 6(3) = 13
-x + 18 = 13
-x = -5
Dividing both sides of the equation by -1, we get:
x = 5
Therefore, the solution to the system of equations is (5, 3).
First, let's multiply the first equation by 4 to make the coefficient of "-x" the same as the coefficient of "4x" in the second equation:
4(-x + 6y) = 4(13)
-4x + 24y = 52
Now we can add this new equation to the second equation to eliminate the variable "x":
(-4x + 24y) + (4x - 10y) = 52 + (-10)
14y = 42
Dividing both sides of the equation by 14, we get:
y = 3
Now we can plug this value of y back into either of the original equations to solve for x. Let's use the first equation:
-x + 6(3) = 13
-x + 18 = 13
-x = -5
Dividing both sides of the equation by -1, we get:
x = 5
Therefore, the solution to the system of equations is (5, 3).
solve the system of equations.
3x+6y=21
-5x+2y=13
(___,___)
3x+6y=21
-5x+2y=13
(___,___)
To solve this system of equations, we can use the method of elimination.
First, let's multiply the first equation by 5 and the second equation by 3:
5(3x + 6y) = 5(21)
3(-5x + 2y) = 3(13)
This simplifies to:
15x + 30y = 105
-15x + 6y = 39
Now we can add these two new equations together to eliminate the variable "x":
(15x + 30y) + (-15x + 6y) = 105 + 39
36y = 144
Dividing both sides of the equation by 36, we get:
y = 4
Now we can substitute the value of y back into either of the original equations to solve for x. Let's use the first equation:
3x + 6(4) = 21
3x + 24 = 21
3x = -3
Dividing both sides of the equation by 3, we get:
x = -1
Therefore, the solution to the system of equations is (-1, 4).
First, let's multiply the first equation by 5 and the second equation by 3:
5(3x + 6y) = 5(21)
3(-5x + 2y) = 3(13)
This simplifies to:
15x + 30y = 105
-15x + 6y = 39
Now we can add these two new equations together to eliminate the variable "x":
(15x + 30y) + (-15x + 6y) = 105 + 39
36y = 144
Dividing both sides of the equation by 36, we get:
y = 4
Now we can substitute the value of y back into either of the original equations to solve for x. Let's use the first equation:
3x + 6(4) = 21
3x + 24 = 21
3x = -3
Dividing both sides of the equation by 3, we get:
x = -1
Therefore, the solution to the system of equations is (-1, 4).
All answers is correct !!!!