To find the solution to the quadratic equation 3x^2 + 3x + 5 = 0, you can use the quadratic formula. The quadratic formula states that for an equation in the form ax^2 + bx + c = 0, the solutions are given by:
x = (-b ± √(b^2-4ac)) / (2a)
For the given equation, a = 3, b = 3, and c = 5. Plugging these values into the quadratic formula:
x = (-3 ± √(3^2-4*3*5)) / (2*3)
x = (-3 ± √(9-60)) / 6
x = (-3 ± √(-51)) / 6
Since the discriminant (b^2-4ac) is negative (-51), it means that the equation has no real solutions. The solutions will be imaginary.
what is the solution to 3x^2+3x+5=0
1 answer