Question

Ten less than twice a number is equal to at most 52. What are all the possible values of the number? Inuk wrote the inequality 2x−10≤52 , where x equals the number, to help solve this problem. Solve his inequality. Use the letter x as your variable and write your x term first.

Note: You will find the option to add a >
, <
, ≥
, or ≤
symbol in the Comparison

Answer 1

no

Answer 2

where x equals the number, to help solve this problem. Solve his inequality. Use the letter x as your variable and write your x term first.

Answer 3

The inequality 2x - 10 ≤ 52 can be solved as follows:

2x ≤ 52 + 10
2x ≤ 62
x ≤ 31

Therefore, the possible values of the number are all real numbers less than or equal to 31.

Answer 4

I apologize for the mistake. Let's solve the inequality correctly.

2x - 10 ≤ 52

Add 10 to both sides:
2x ≤ 52 + 10
2x ≤ 62

Now divide both sides by 2:
x ≤ 62/2
x ≤ 31

So the possible values of the number are all real numbers less than or equal to 31.

Answer 5

Apologies for the confusion.

To solve the inequality 2x - 10 ≤ 52, we will isolate the variable x:

2x - 10 ≤ 52

Add 10 to both sides:
2x ≤ 52 + 10
2x ≤ 62

Divide both sides by 2:
x ≤ 62/2
x ≤ 31

Therefore, the value of the number (x) must be less than or equal to 31.