h= -25/36x^2+16 2/3x

Answer 1

It looks like you have presented the equation of a quadratic function in the form:

h(x) = ax^2 + bx + c

The coefficients and the variable 'x' seem to be provided with mixed numbers and fractions. Before we can do anything with this equation, let's get it into a more standard form with all coefficients expressed as decimals or improper fractions.

The given quadratic function is:

h(x) = -25/36x^2 + 16 2/3x

First, we need to convert the mixed number 16 2/3 to an improper fraction. To do this, multiply the whole number (16) by the denominator of the fraction (3), then add the numerator of the fraction (2):

16 * 3 + 2 = 48 + 2 = 50

Now we have 50/3 as the improper fraction equivalent to the mixed number 16 2/3. So the function becomes:

h(x) = -25/36x^2 + 50/3x

If necessary or desired, you can simplify or perform operations on this quadratic function, such as finding its vertex, axis of symmetry, x-intercepts, or sketching its graph. If you want to do any of these, please let me know what specifically you're looking for.