To determine how many solutions are in the solution set for the equation \(3x^2 = 21\), let's solve the equation.
First, divide both sides of the equation by 3 to isolate \(x^2\):
\(3x^2 = 21\)
\(x^2 = 7\)
Next, take the square root of both sides to solve for x. Remember, there are two square roots for any positive number, a positive and a negative root:
\(\sqrt{x^2} = \sqrt{7}\)
\(x = \pm\sqrt{7}\)
This gives us two solutions for x: \(x = \sqrt{7}\) and \(x = -\sqrt{7}\).
Therefore, the solution set contains two solutions.
Show how many solutions are in the solution set for the equation 3x2=21 .(1 point)
Responses
one
one
zero
zero
two
two
infinitely many
1 answer