To calculate the volume of a cone, you can use the formula:
\[ V = \frac{1}{3} \pi r^2 h \]
where \(V\) is the volume, \(r\) is the radius of the base of the cone, and \(h\) is the height of the cone.
You stated the radius \(r\) is 5 inches and the height \(h\) is 9 inches.
Plugging these values into the formula, we get:
\[ V = \frac{1}{3} \pi (5\text{ in})^2 (9\text{ in}) \]
\[ V = \frac{1}{3} \pi (25\text{ in}^2) (9\text{ in}) \]
\[ V = \frac{1}{3} \pi (225\text{ in}^3) \]
\[ V = 75\pi\text{ in}^3 \]
To get a numerical value, we can approximate \(\pi\) as 3.14159:
\[ V \approx 75 \times 3.14159\text{ in}^3 \]
\[ V \approx 235.5\text{ in}^3 \]
Thus, the volume of the cone is approximately 235.5 cubic inches.
What is the volume of the cone?
(1 point)
Responses
47.1 cubic inches
47.1 cubic inches
942 cubic inches
942 cubic inches
235.5 cubic inches
235.5 cubic inches
423.9 cubic inches
radiuis is 5 and height 9
1 answer