Let's call the number we're looking for "x." The problem states that ten less than twice this number is at least 52. We can set up an inequality to represent this relationship:
Twice the number: 2x
Ten less than twice the number: 2x - 10
At least 52: ≥ 52
So the inequality would look like this:
2x - 10 ≥ 52
Now, we can solve for x:
First, add 10 to both sides of the inequality to isolate the term with x on one side:
2x - 10 + 10 ≥ 52 + 10
2x ≥ 62
Next, divide both sides by 2 to solve for x:
2x / 2 ≥ 62 / 2
x ≥ 31
The solution to the inequality is x ≥ 31, which means that all possible values of the number are 31 and any larger number. The inequality that could be used to solve this problem is:
2x - 10 ≥ 52
Ten less than twice a number is equal to at least 52. What are all the possible values of the number? Write an inequality that could be used to solve this problem
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