Asked by Alyssa
Solve |6x – 7| < = 25 and write interval notation for the solution set.
Answers
Answered by
Marth
Undo the absolute value:
6x - 7 <= 25
and 6x - 7 >= -25
Now solve for x:
6x - 7 <= 25
6x <= 32
x <= 16/3
6x-7 >= -25
6x >= -18
6x >= -3
-3 <= x <= 16/3
Therefore, interval notation is [-3, 16/3]. Brackets are used because x can equal -3 and 16/3.
6x - 7 <= 25
and 6x - 7 >= -25
Now solve for x:
6x - 7 <= 25
6x <= 32
x <= 16/3
6x-7 >= -25
6x >= -18
6x >= -3
-3 <= x <= 16/3
Therefore, interval notation is [-3, 16/3]. Brackets are used because x can equal -3 and 16/3.
Answered by
Reiny
|6x – 7| ≤ 25
so 6x-7 ≤ 25 AND -6x+7 ≤ 25
6x ≤ 32 AND -6x ≤ 18
x ≤ 16/3 AND x ≥ -3
-3 ≤ x ≤ 16/3
so 6x-7 ≤ 25 AND -6x+7 ≤ 25
6x ≤ 32 AND -6x ≤ 18
x ≤ 16/3 AND x ≥ -3
-3 ≤ x ≤ 16/3
Answered by
Alyssa
What would be the answer in interval notation?
A. [-16/3,3]
B. [-3,16/3]
C. (-infinity, -16/3 U [3, infinity)
D. (-infinity, -3] U [16/3,infinity)
Based on the answer you provided I am goin to say B. Am I correct? Thanks!
A. [-16/3,3]
B. [-3,16/3]
C. (-infinity, -16/3 U [3, infinity)
D. (-infinity, -3] U [16/3,infinity)
Based on the answer you provided I am goin to say B. Am I correct? Thanks!
Answered by
Marth
"Interval notation is [-3, 16/3]."
Yes, B is correct.
Yes, B is correct.
Answered by
Alyssa
Thank you!
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