Solve |6x – 7| < = 25 and write interval notation for the solution set.

Answer 1

Undo the absolute value:

6x - 7 <= 25

and 6x - 7 >= -25

Now solve for x:
6x - 7 <= 25
6x <= 32
x <= 16/3

6x-7 >= -25
6x >= -18
6x >= -3

-3 <= x <= 16/3

Therefore, interval notation is [-3, 16/3]. Brackets are used because x can equal -3 and 16/3.

Answer 2

|6x – 7| ≤ 25
so 6x-7 ≤ 25 AND -6x+7 ≤ 25
6x ≤ 32 AND -6x ≤ 18
x ≤ 16/3 AND x ≥ -3

-3 ≤ x ≤ 16/3

Answer 3

What would be the answer in interval notation?

A. [-16/3,3]
B. [-3,16/3]
C. (-infinity, -16/3 U [3, infinity)
D. (-infinity, -3] U [16/3,infinity)

Based on the answer you provided I am goin to say B. Am I correct? Thanks!

Answer 4

"Interval notation is [-3, 16/3]."

Yes, B is correct.

Answer 5

Thank you!