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use the formula for the surface area of a sphere to find the surface area of a basketball that has a diameter of 9.2 inches. Use 3.14 pi and round your answer to the nearest hundredth, if necessary.
a 265.77 in^2
b 84.64 in^2
c 1,063.08 in^2
d 66.44 in^2
a 265.77 in^2
b 84.64 in^2
c 1,063.08 in^2
d 66.44 in^2
Answers
Answered by
GPT-4 Turbo
The formula for the surface area of a sphere is given by:
\( A = 4\pi r^2 \)
where \( A \) is the surface area of the sphere and \( r \) is the radius of the sphere. Since we know the diameter of the basketball is 9.2 inches, we can find the radius by dividing the diameter by 2:
\( r = \frac{diameter}{2} = \frac{9.2 \text{ inches}}{2} = 4.6 \text{ inches} \)
Now let's use the formula to find the surface area, remembering to use 3.14 for \( \pi \):
\( A = 4 \times 3.14 \times (4.6 \text{ inches})^2 \)
\( A = 4 \times 3.14 \times 21.16 \text{ inches}^2 \)
\( A = 12.56 \times 21.16 \text{ inches}^2 \)
\( A = 265.7936 \text{ inches}^2 \)
Rounded to the nearest hundredth, the surface area of the basketball is approximately:
\( A \approx 265.79 \text{ inches}^2 \)
So the correct answer is:
a) 265.77 in^2 (Note that there's a slight difference due to rounding, but this is the closest option to our calculated value.)
\( A = 4\pi r^2 \)
where \( A \) is the surface area of the sphere and \( r \) is the radius of the sphere. Since we know the diameter of the basketball is 9.2 inches, we can find the radius by dividing the diameter by 2:
\( r = \frac{diameter}{2} = \frac{9.2 \text{ inches}}{2} = 4.6 \text{ inches} \)
Now let's use the formula to find the surface area, remembering to use 3.14 for \( \pi \):
\( A = 4 \times 3.14 \times (4.6 \text{ inches})^2 \)
\( A = 4 \times 3.14 \times 21.16 \text{ inches}^2 \)
\( A = 12.56 \times 21.16 \text{ inches}^2 \)
\( A = 265.7936 \text{ inches}^2 \)
Rounded to the nearest hundredth, the surface area of the basketball is approximately:
\( A \approx 265.79 \text{ inches}^2 \)
So the correct answer is:
a) 265.77 in^2 (Note that there's a slight difference due to rounding, but this is the closest option to our calculated value.)
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