Asked by walpaper test
Use the formula for the volume of a sphere to find the volume of a basketball that has a diameter of 9.2 inches. Use 3.14 as an approximation for pi and round your answer to the nearest hundredth, if necessary.(1 point)
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thats wrong
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GPT-4 Turbo
The formula for the volume of a sphere is given by:
\[ V = \frac{4}{3} \pi r^3 \]
where \( V \) is the volume and \( r \) is the radius of the sphere.
Since the diameter of the basketball is given as 9.2 inches, the radius \( r \) will be half of the diameter:
\[ r = \frac{d}{2} = \frac{9.2 \text{ inches}}{2} = 4.6 \text{ inches} \]
Now, we can calculate the volume:
\[ V = \frac{4}{3} \times 3.14 \times (4.6 \text{ inches})^3 \]
\[ V = \frac{4}{3} \times 3.14 \times (4.6 \text{ inches} \times 4.6 \text{ inches} \times 4.6 \text{ inches}) \]
\[ V = \frac{4}{3} \times 3.14 \times 97.336 \text{ inches}^3 \]
\[ V = 4.18666667 \times 3.14 \times 97.336 \]
\[ V \approx 1287.1693332 \text{ inches}^3 \]
Rounding to the nearest hundredth:
\[ V \approx 1287.17 \text{ inches}^3 \]
So, the volume of the basketball is approximately 1287.17 cubic inches.
\[ V = \frac{4}{3} \pi r^3 \]
where \( V \) is the volume and \( r \) is the radius of the sphere.
Since the diameter of the basketball is given as 9.2 inches, the radius \( r \) will be half of the diameter:
\[ r = \frac{d}{2} = \frac{9.2 \text{ inches}}{2} = 4.6 \text{ inches} \]
Now, we can calculate the volume:
\[ V = \frac{4}{3} \times 3.14 \times (4.6 \text{ inches})^3 \]
\[ V = \frac{4}{3} \times 3.14 \times (4.6 \text{ inches} \times 4.6 \text{ inches} \times 4.6 \text{ inches}) \]
\[ V = \frac{4}{3} \times 3.14 \times 97.336 \text{ inches}^3 \]
\[ V = 4.18666667 \times 3.14 \times 97.336 \]
\[ V \approx 1287.1693332 \text{ inches}^3 \]
Rounding to the nearest hundredth:
\[ V \approx 1287.17 \text{ inches}^3 \]
So, the volume of the basketball is approximately 1287.17 cubic inches.
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