The volume V of a cone can be calculated using the formula:
V = (1/3)πr^2h
where r is the radius of the base of the cone and h is the height of the cone.
Given r = 5 cm and h = 9 cm, we can plug these values into the formula to calculate the volume:
V = (1/3)π(5 cm)^2(9 cm)
V = (1/3)π(25 cm^2)(9 cm)
V = (1/3)π(225 cm^3)
V = 75π cm^3
Since π (pi) is approximately 3.14159, we can calculate the numerical value of the volume:
V = 75 * 3.14159 cm^3
V ≈ 235.62 cm^3
Rounded to the nearest tenth, the volume of the cone is approximately 235.6 cubic centimeters.
what is the volume of the cone in cubic centimeters? round your answer to the nearest tenth. H=9cm R=5cm
8 answers
wrong
I apologize for the confusion. Let's recalculate the volume of the cone correctly.
Given:
Radius (r) = 5 cm
Height (h) = 9 cm
Volume (V) of a cone is given by the formula:
\[ V = \frac{1}{3}\pi r^2 h \]
Using the given values, we get:
\[ V = \frac{1}{3}\pi (5\, \text{cm})^2 (9\, \text{cm}) \]
\[ V = \frac{1}{3}\pi (25\, \text{cm}^2) (9\, \text{cm}) \]
\[ V = \frac{1}{3}\pi (225\, \text{cm}^3) \]
\[ V = 75\pi \, \text{cm}^3 \]
Computing the value using π ≈ 3.14159, we get:
\[ V ≈ 75 \times 3.14159\, \text{cm}^3 \]
\[ V ≈ 235.61925\, \text{cm}^3 \]
Rounded to the nearest tenth:
\[ V ≈ 235.6\, \text{cm}^3 \]
It seems the initial calculation was accurate. The volume of the cone is approximately 235.6 cubic centimeters when rounded to the nearest tenth.
Given:
Radius (r) = 5 cm
Height (h) = 9 cm
Volume (V) of a cone is given by the formula:
\[ V = \frac{1}{3}\pi r^2 h \]
Using the given values, we get:
\[ V = \frac{1}{3}\pi (5\, \text{cm})^2 (9\, \text{cm}) \]
\[ V = \frac{1}{3}\pi (25\, \text{cm}^2) (9\, \text{cm}) \]
\[ V = \frac{1}{3}\pi (225\, \text{cm}^3) \]
\[ V = 75\pi \, \text{cm}^3 \]
Computing the value using π ≈ 3.14159, we get:
\[ V ≈ 75 \times 3.14159\, \text{cm}^3 \]
\[ V ≈ 235.61925\, \text{cm}^3 \]
Rounded to the nearest tenth:
\[ V ≈ 235.6\, \text{cm}^3 \]
It seems the initial calculation was accurate. The volume of the cone is approximately 235.6 cubic centimeters when rounded to the nearest tenth.
whats the volume of a cone with a R of 3 and a H of 7
To calculate the volume of a cone with a radius (R) of 3 cm and a height (H) of 7 cm, we would use the formula for the volume (V) of a cone:
\[ V = \frac{1}{3}\pi r^2 h \]
where \( r \) is the radius and \( h \) is the height. Plugging in the values for the radius and height, we get:
\[ V = \frac{1}{3}\pi (3\, \text{cm})^2 (7\, \text{cm}) \]
\[ V = \frac{1}{3}\pi (9\, \text{cm}^2) (7\, \text{cm}) \]
\[ V = \frac{1}{3}\pi (63\, \text{cm}^3) \]
\[ V = 21\pi\, \text{cm}^3 \]
Now, using the approximate value for π (pi), which is 3.14159, we can estimate the volume:
\[ V \approx 21 \times 3.14159\, \text{cm}^3 \]
\[ V \approx 65.97319\, \text{cm}^3 \]
To round this to the nearest whole number:
\[ V \approx 66\, \text{cm}^3 \]
So the volume of the cone is approximately 66 cubic centimeters.
\[ V = \frac{1}{3}\pi r^2 h \]
where \( r \) is the radius and \( h \) is the height. Plugging in the values for the radius and height, we get:
\[ V = \frac{1}{3}\pi (3\, \text{cm})^2 (7\, \text{cm}) \]
\[ V = \frac{1}{3}\pi (9\, \text{cm}^2) (7\, \text{cm}) \]
\[ V = \frac{1}{3}\pi (63\, \text{cm}^3) \]
\[ V = 21\pi\, \text{cm}^3 \]
Now, using the approximate value for π (pi), which is 3.14159, we can estimate the volume:
\[ V \approx 21 \times 3.14159\, \text{cm}^3 \]
\[ V \approx 65.97319\, \text{cm}^3 \]
To round this to the nearest whole number:
\[ V \approx 66\, \text{cm}^3 \]
So the volume of the cone is approximately 66 cubic centimeters.
no use 3.14 for pi and please do step by step
What is the volume of the cone in cubic centimeters? Use 3.14 for pi. Round your answer to the nearest tenth. (1 point)
cubic centimeters
cubic centimeters
bro its wrong use 3.14 for pi and round it off to the nearest tenth