The correct response is:
The equation |x+2|=0 will have one solution and the inequality |x+2|≥0 will have a range of solutions.
Explanation:
For the equation |x+2| = 0, the only solution is x = -2, because the absolute value of a number is zero if and only if the number itself is zero. So the expression inside the absolute value, (x+2), must be zero.
For the inequality |x+2| ≥ 0, this is always true for all real numbers x because the absolute value is by definition non-negative. This means that any real number x will satisfy the inequality. Therefore, the inequality |x+2| ≥ 0 has a range of solutions that includes all real numbers.
How is solving |x+2|=0
different from solving |x+2|≥0
?(1 point)
Responses
There is no difference as they both will have only one solution
There is no difference as they both will have only one solution
There is no difference as they are both absolute values
There is no difference as they are both absolute values
The equation |x+2|=0
will have two solutions and the inequality |x+2|≥0
will have a range of solutions.
The equation start absolute value x plus 2 end absolute value is equal to 0 will have two solutions and the inequality start absolute value x plus 2 end absolute value is greater than or equal to 0 will have a range of solutions.
The equation |x+2|=0
will have one solution and the inequality |x+2|≥0
will have a range of solutions.
1 answer