Question

sole the systems of equations 8x-3y=-22 y=10+4x (__,__) (1point)

Answer 1

To solve the system of equations, substitute the value of y from the second equation into the first equation:

8x - 3(10 + 4x) = -22

8x - 30 - 12x = -22

Combine like terms:

-4x - 30 = -22

Add 30 to both sides:

-4x = 8

Divide both sides by -4:

x = -2

Now, substitute the value of x back into the second equation to find y:

y = 10 + 4(-2)
y = 10 - 8
y = 2

So, the solution to the system of equations is (x, y) = (-2, 2).

Answer 2

sole the systems of equations 5x+2y=14 x-6y=22 (__,__) (1point)

Answer 3

To solve the system of equations, you can use the method of substitution or elimination. Let's use the method of substitution.

From the second equation, we can solve for x:

x = 22 + 6y

Now substitute this value of x into the first equation:

5(22 + 6y) + 2y = 14

Distribute multiplication:

110 + 30y + 2y = 14

Combine like terms:

32y + 110 = 14

Subtract 110 from both sides:

32y = -96

Divide both sides by 32:

y = -3

Now substitute the value of y back into the second equation to find x:

x - 6(-3) = 22

x + 18 = 22

Subtract 18 from both sides:

x = 22 - 18

x = 4

So, the solution to the system of equations is (x, y) = (4, -3).